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Protect against zero length loops giving a kernel call failure

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This commit is contained in:
Peter Boyle 2018-09-10 11:20:07 +01:00
parent f27b9347ff
commit b5329d8852
1 changed files with 14 additions and 12 deletions
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26
lib/threads/Pragmas.h
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@ -108,18 +108,20 @@ void LambdaApply(uint64_t base, uint64_t Num, lambda Lambda)
#define accelerator_loopN( iterator, num, ... ) \ #define accelerator_loopN( iterator, num, ... ) \
typedef decltype(num) Iterator; \ typedef decltype(num) Iterator; \
auto lambda = [=] accelerator (Iterator iterator) mutable { \ if ( num > 0 ) { \
__VA_ARGS__; \ auto lambda = [=] accelerator (Iterator iterator) mutable { \
}; \ __VA_ARGS__; \
Iterator base = 0; \ }; \
Iterator num_block = (num+gpu_threads-1)/gpu_threads; \ Iterator base = 0; \
LambdaApply<<<num_block,gpu_threads>>>(base,num,lambda); \ Iterator num_block = (num+gpu_threads-1)/gpu_threads; \
cudaDeviceSynchronize(); \ LambdaApply<<<num_block,gpu_threads>>>(base,num,lambda); \
cudaError err = cudaGetLastError(); \ cudaDeviceSynchronize(); \
if ( cudaSuccess != err ) { \ cudaError err = cudaGetLastError(); \
printf("Cuda error %s\n",cudaGetErrorString( err )); \ if ( cudaSuccess != err ) { \
exit(0); \ printf("Cuda error %s\n",cudaGetErrorString( err )); \
} exit(0); \
} \
}
#define cpu_loop( iterator, range, ... ) thread_loop( (auto iterator = range.begin();iterator<range.end();iterator++), { __VA_ARGS__ }); #define cpu_loop( iterator, range, ... ) thread_loop( (auto iterator = range.begin();iterator<range.end();iterator++), { __VA_ARGS__ });