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Fixing Laplace flopcount Minor cleanup
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@@ -768,7 +768,7 @@ public:
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double volume=1; for(int mu=0;mu<Nd;mu++) volume=volume*latt4[mu];
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// double flops=(1146.0*volume)/2;
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double flops=(2*8*216.0*volume);
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double flops=(2*2*8*216.0*volume);
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double mf_hi, mf_lo, mf_err;
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timestat.statistics(t_time);
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