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Add function to return full type as std::string

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Also works for nested templates. I find it useful for debugging.
Possible usage:

std::cout << "getTypename<AType>() = " << getTypename<Atype>() << std::endl;
std::cout << "getTypename<decltype(AnInstance)>() = " << getTypename<decltype(AnInstance)>() << std::endl;
This commit is contained in:
Daniel Richtmann 2018-01-29 17:34:26 +01:00
parent faf4278019
commit 1cb745c8dc
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GPG Key ID: B33C490AF0772057
1 changed files with 20 additions and 0 deletions
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20
lib/tensors/Tensor_traits.h
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@ -23,6 +23,7 @@ Author: Christopher Kelly <ckelly@phys.columbia.edu>
#define GRID_MATH_TRAITS_H
#include <type_traits>
#include <cxxabi.h>
namespace Grid {
@ -288,6 +289,25 @@ namespace Grid {
enum { value = sizeof(real_scalar_type)/sizeof(float) };
};
template<typename T> std::string getTypename() {
typedef typename std::remove_reference<T>::type TWoRef;
std::unique_ptr<char, void (*)(void *)> own(abi::__cxa_demangle(typeid(TWoRef).name(), nullptr, nullptr, nullptr), std::free);
std::string r = own != nullptr ? own.get() : typeid(TWoRef).name();
if(std::is_const<TWoRef>::value)
r += " const";
if(std::is_volatile<TWoRef>::value)
r += " volatile";
if(std::is_lvalue_reference<T>::value)
r += "&";
else if(std::is_rvalue_reference<T>::value)
r += "&&";
return r;
}
}
#endif